#Font to dictionary by Sean McManus / www.sean.co.uk / CC BY-NC-SA
# -*- coding: utf-8 -*-

import pygame
pygame.init()
canvas=pygame.display.set_mode((100,100))
pygame.mouse.set_visible(0)

char_set = "QWERTYUIOP ASDFGHJKL ZXCVBNM 1234567890-= !$%^&*()_+"
char_set += "[]{} ;'#:@~ ,./<>?\"\\" #Extra \ before " and \
font_dictionary = dict()

for letter in char_set: #main dictionary creation loop
    canvas.fill((0,0,0)) #clear the canvas
    fontObj = pygame.font.Font(\
        '/usr/share/fonts/truetype/freefont/FreeSans.ttf',9)
    textSurface = fontObj.render(letter,True,(255,255,255),(0,0,0))
    textRectObj = textSurface.get_rect()
    canvas.blit(textSurface, textRectObj)
    pygame.display.update() #display the letter

    letter_data = []
    for y in range(8): #check each row of the letter on canvas
        letter_row=[]
        for x in range(8): #each x position of letter on canvas
            colour = canvas.get_at((x,y+2))
            if colour[0]>200:
                letter_row.append(1)
            elif colour[0]>100: 
                letter_row.append(0.75)
            elif colour[0]: 
                letter_row.append(0.15)
            else:
                letter_row.append(0)
        letter_data.append(letter_row)

    for x in range(7,-1,-1): # Trim excess space on right of letter
        column=[letter_data[y][x] for y in range(8)]
        if max(column)==0:
            for i in range(8):
                del letter_data[i][x]

    font_dictionary[letter]=letter_data
  
font_dictionary[' ']=[[0]*4]*8 #space gets trimmed to empty otherwise
font_dictionary['@']=[[0,1,1,1,1,1,0],[1,1,0,0,0,1,1],[1,1,0,1,1,1,1],\
[1,1,0,1,0,0,1],[1,1,0,1,1,1,1],[1,1,0,0,0,0,0],[0,1,1,1,1,1,0],[0]*7]

pygame.quit()
print font_dictionary